Page 12 - Dört Dörtlük Konu Pekiştirme Testi - Kimya 9

Simyadan Kimyaya - Kimya Disiplinleri ve
.ÿ0<$ .LP\DFÖODUÖQ dDOÖþPD $ODQODUÖ ÇÖZÜMLÜ SORULAR

4. 6LP\DF×ODU XÿUDüODU× VRQXFXQGD NLP\DGD NXOODQ×ODQ oHüLWOL .LP\D GLVLSOLQOHUL YH oDOÖþPD DODQODUÖ LOH LOJLOL DþDāÖGD YHUL-
DUDo JHUHoOHUL JHOLüWLUPLü YH ED]× \|QWHP YH WHNQLNOHUL NXOODQ OHQOHUGHQ KDQJLVL \DQOÖþWÖU"
P×üODUG×U
Kimya disiplini dDOÖþPD DODQODUÖ
%XQD J|UH A) )L]LNRNLP\D (QGVWULGH NXOODQ×ODQ ELUoRN HQGVW
x %RUFDP x 7HIORQ x 3LO
UL\HO PDGGHQLQ UHWLP VUHFL LOH LOJL
x %UHW x 'L\DOL] x 6DQWULIMOHPH
OHQHQ NLP\D GDO×G×U
\XNDUÖGD YHULOHQ PDGGH DUDo JHUHo YH \|QWHPOHUGHQ
% %L\RNLP\D %WQ FDQO×ODU×Q \DS×V×QGD \HU DODQ
NDo WDQHVL VLP\D G|QHPLQGH NXOODQÖOPDPÖþWÖU"
NLP\DVDOODU× YH NLP\DVDO VUHoOHUL
$ % & ' ( LQFHOH\HQ NLP\D GDO×G×U
Çözüm: & $QDOLWLN NLP\D %LU PDGGH\L ROXüWXUDQ ELOHüHQOHUL
YH EX ELOHüHQOHULQ QLFHOLN YH QLWH
%RUFDP ×V×\D GD\DQDNO× FDPG×U 7HIORQ SROLPHUOHüPH U
QGU %X LNL PDGGH VLP\D G|QHPLQGH NXOODQ×OPDP×üW×U OLNOHULQL LQFHOH\HQ NLP\D GDO×G×U
' $QRUJDQLN NLP\D 2UJDQLN ROPD\DQ JHQHOOLNOH NDUERQ
ýPELN YH NUR]H VLP\D G|QHPL DUDo JHUHoOHUL LNHQ EUHW R
G|QHPGH NXOODQ×OPDP×üW×U LoHUPH\HQ ELOHüLNOHULQ |]HOOLNOHULQL
YH WHSNLPHOHULQL LQFHOH\HQ NLP\D
3LO JQP]GH NXOODQ×ODQ NLP\DVDO HQHUML\L HOHNWULN HQHUML GDO×G×U
VLQH G|QüWUHQ HQHUML GHSRODPD DUDF×G×U 6LP\D G|QHPLQ
( 2UJDQLN NLP\D .DUERQ HOHPHQWLQLQ ROXüWXUGXÿX
GH NXOODQ×OPDP×üW×U
RUJDQLN ELOHüLNOHULQ \DS×ODU×Q×
6]PH\L HVDV DODQ GL\DOL] YH PHUNH]NDo NXYYHWLQL HVDV DODQ |]HOOLNOHULQL WHSNLPHOHULQL LQFH
VDQWULIMOHPH GH JQP]GH NXOODQ×ODQ \|QWHPOHUGHQGLU OH\HQ YH ELOHüLNOHU VHQWH]OH\HQ
NLP\D GDO×G×U
&HYDS (

Çözüm:
$þDāÖGD YHULOHQ oDOÖþPDODUGDQ KDQJLVL NLP\DQÖQ oDOÖþPD )L]LNRNLP\D .LP\DVDO WHSNLPHOHUGHNL HQHUML GHÿLüLPOHUL LOH
DODQÖQD JLUPH]" EDV×Qo V×FDNO×N GHULüLP JLEL HWNHQOHULQ NLP\DVDO WHSNLPHOHU
]HULQGHNL HWNLOHULQL LQFHOH\HQ NLP\D GLVLSOLQLGLU
$ ýQüDDW J×GD YH N×UWDVL\H JLEL DODQODUGD PDGGHOHUL
UHQNOHQGLUPHN LoLQ NXOODQ×ODQ PDGGH UHWLPL $ üHoHQHÿLQGH YHULOHQ Do×NODPD HQGVWUL\HO NLP\D\D DLWWLU

% 'DKD GD\DQ×NO× YH oHYUH\H ]DUDUV×] LSOLN UHWLPL
6RUXGD EDKVHGLOPH\HQ SROLPHU NLP\DV× GD NLP\D GLVLS
& +DVWDO×NODUD NDUü× FDQO×ODU× NRUX\DQ KDVWDO×NODU× |QOH OLQLGLU 3ROLPHUOHU NoN PROHNOOHULQ ]LQFLU üHNOLQGH ELUEL
\HQ YH\D L\LOHüWLUHQ PDGGHOHULQ UHWLPL ULQH EDÿODQPDV×\OD ROXüDQ E\N PROHNOOHUGLU 3ROLPHU
NLP\DV× VHOOR] QLüDVWD YH NDXoXN JLEL GRÿDO SROLPHUOHULQ
' $W×N VXODU×Q WHPL]OHQHUHN NXOODQ×O×U GXUXPD JHWLULOPHVL
\DQ×QGD \DSD\ SROLPHUOHULQ \DS×ODU×Q× |]HOOLNOHULQL NXOOD
LoLQ \DS×ODQ oDO×üPDODU
Q×P DODQODU×Q× LQFHOH\HQ NLP\D GDO×G×U 3ODVWLNOHU NDXoXN
( <HU NDEXÿXQGDNL N×U×OPDODU×Q WHVSLWL ODU SROLPHU NLP\DV×Q×Q XÿUDü DODQ×G×U
Çözüm: &HYDS $

<HU NDEXÿX KDUHNHWOHUL ID\ KDWODU× MHRORML PKHQGLVOLÿLQLQ
oDO×üPD DODQODU×QGDQG×U .LP\DQ×Q oDO×üPD DODQ×QD JLUPH]

.LP\DQ×Q EDüO×FD oDO×üPD DODQODU×
$U×W×P ER\D HQGVWULVL SHWURNLP\D LODo HQGVWULVL PRELO\D
HQGVWULVL WHNVWLO HQGVWULVL JEUH HQGVWULVL LQüDDW J×GD
YH N×UWDVL\H JLEL DODQODUGD UHWLOHQ PDO]HPHOHULQ UHQNOHQGL
ULOPHVL LoLQ NXOODQ×ODQ PDGGH UHWLPL %R\D HQGVWULVL
'DKD GD\DQ×NO× YH oHYUH\H ]DUDUV×] LSOLN UHWLPL 7HNVWLO
HQGVWULVL
+DVWDO×NODUD NDUü× FDQO×ODU× NRUX\DQ KDVWDO×NODU× |QOH\HQ
YH\D L\LOHüWLUHQ PDGGHOHULQ UHWLPL ýODo HQGVWULVL
$W×N VXODU×Q WHPL]OHQHUHN NXOODQ×O×U GXUXPD JHWLULOPHVL LoLQ
\DS×ODQ oDO×üPDODU $U×W×P

&HYDS (

10